Base | Representation |
---|---|
bin | 11110000101111110100… |
… | …01010000101101101111 |
3 | 10122211221022112111102121 |
4 | 33002333101100231233 |
5 | 113420113241433312 |
6 | 2111002532333411 |
7 | 134463340353022 |
oct | 17027721205557 |
9 | 3584838474377 |
10 | 1034001124207 |
11 | 369576750847 |
12 | 148490a74267 |
13 | 76676586c4c |
14 | 380900191b9 |
15 | 1bd6b788707 |
hex | f0bf450b6f |
1034001124207 has 2 divisors, whose sum is σ = 1034001124208. Its totient is φ = 1034001124206.
The previous prime is 1034001124183. The next prime is 1034001124213. The reversal of 1034001124207 is 7024211004301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1034001124207 - 211 = 1034001122159 is a prime.
It is a super-2 number, since 2×10340011242072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1034001122207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517000562103 + 517000562104.
It is an arithmetic number, because the mean of its divisors is an integer number (517000562104).
Almost surely, 21034001124207 is an apocalyptic number.
1034001124207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1034001124207 is an equidigital number, since it uses as much as digits as its factorization.
1034001124207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 1034001124207 its reverse (7024211004301), we get a palindrome (8058212128508).
The spelling of 1034001124207 in words is "one trillion, thirty-four billion, one million, one hundred twenty-four thousand, two hundred seven".
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