10341113100 has 72 divisors (see below), whose sum is σ = 30016151760. Its totient is φ = 2748794880.

The previous prime is 10341113093. The next prime is 10341113113. The reversal of 10341113100 is 131114301.

It is a super-2 number, since 2×10341113100² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 10341113100.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 38836 + ... + 148964.

Almost surely, 2^10341113100 is an apocalyptic number.

10341113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10341113100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15008075880).

10341113100 is an abundant number, since it is smaller than the sum of its proper divisors (19675038660).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10341113100 is a wasteful number, since it uses less digits than its factorization.

10341113100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110459 (or 110452 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 10341113100 its reverse (131114301), we get a palindrome (10472227401).

The spelling of 10341113100 in words is "ten billion, three hundred forty-one million, one hundred thirteen thousand, one hundred".