Base | Representation |
---|---|
bin | 1001011001111100101110… |
… | …1111001111101101000101 |
3 | 1100121121222020220211111121 |
4 | 2112133023233033231011 |
5 | 2323413144014111123 |
6 | 33554435311033541 |
7 | 2115066433252063 |
oct | 226371357175505 |
9 | 40547866824447 |
10 | 10341404441413 |
11 | 3327846230a41 |
12 | 11b029750b8b1 |
13 | 5a0261cb18b6 |
14 | 27a753189033 |
15 | 12e00c55975d |
hex | 967cbbcfb45 |
10341404441413 has 2 divisors, whose sum is σ = 10341404441414. Its totient is φ = 10341404441412.
The previous prime is 10341404441363. The next prime is 10341404441477. The reversal of 10341404441413 is 31414440414301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10020757451364 + 320646990049 = 3165558^2 + 566257^2 .
It is a cyclic number.
It is not a de Polignac number, because 10341404441413 - 29 = 10341404440901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10341404448413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5170702220706 + 5170702220707.
It is an arithmetic number, because the mean of its divisors is an integer number (5170702220707).
Almost surely, 210341404441413 is an apocalyptic number.
It is an amenable number.
10341404441413 is a deficient number, since it is larger than the sum of its proper divisors (1).
10341404441413 is an equidigital number, since it uses as much as digits as its factorization.
10341404441413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36864, while the sum is 34.
Adding to 10341404441413 its reverse (31414440414301), we get a palindrome (41755844855714).
The spelling of 10341404441413 in words is "ten trillion, three hundred forty-one billion, four hundred four million, four hundred forty-one thousand, four hundred thirteen".
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