10341431120431 has 2 divisors, whose sum is σ = 10341431120432. Its totient is φ = 10341431120430.

The previous prime is 10341431120413. The next prime is 10341431120459. The reversal of 10341431120431 is 13402113414301.

10341431120431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (10341431120413) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (10341431120459) can be obtained adding 10341431120431 to its sum of digits (28).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10341431120431 - 2⁵ = 10341431120399 is a prime.

It is a super-2 number, since 2×10341431120431² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10341431120431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10341431120131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5170715560215 + 5170715560216.

It is an arithmetic number, because the mean of its divisors is an integer number (5170715560216).

Almost surely, 2^{10341431120431} is an apocalyptic number.

10341431120431 is a deficient number, since it is larger than the sum of its proper divisors (1).

10341431120431 is an equidigital number, since it uses as much as digits as its factorization.

10341431120431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 10341431120431 its reverse (13402113414301), we get a palindrome (23743544534732).

The spelling of 10341431120431 in words is "ten trillion, three hundred forty-one billion, four hundred thirty-one million, one hundred twenty thousand, four hundred thirty-one".