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10341531941549 is a prime number
BaseRepresentation
bin1001011001111101001101…
…0101100111101010101101
31100121122022010211111210212
42112133103111213222231
52323413424134112144
633554500103512205
72115102542061434
oct226372325475255
940548263744725
1010341531941549
1133279011a5756
1211b0312158665
135a0282533573
1427a76609811b
1512e01884249e
hex967d3567aad

10341531941549 has 2 divisors, whose sum is σ = 10341531941550. Its totient is φ = 10341531941548.

The previous prime is 10341531941497. The next prime is 10341531941551. The reversal of 10341531941549 is 94514913514301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6733469681449 + 3608062260100 = 2594893^2 + 1899490^2 .

It is a cyclic number.

It is not a de Polignac number, because 10341531941549 - 236 = 10272812464813 is a prime.

Together with 10341531941551, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10341531941497 and 10341531941506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10341531941749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5170765970774 + 5170765970775.

It is an arithmetic number, because the mean of its divisors is an integer number (5170765970775).

Almost surely, 210341531941549 is an apocalyptic number.

It is an amenable number.

10341531941549 is a deficient number, since it is larger than the sum of its proper divisors (1).

10341531941549 is an equidigital number, since it uses as much as digits as its factorization.

10341531941549 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 50.

The spelling of 10341531941549 in words is "ten trillion, three hundred forty-one billion, five hundred thirty-one million, nine hundred forty-one thousand, five hundred forty-nine".