Base | Representation |
---|---|
bin | 10111100000111110010011… |
… | …111101111010111000101101 |
3 | 111120011221200022100212100212 |
4 | 113200332103331322320231 |
5 | 102023422202000044432 |
6 | 1003542541305232205 |
7 | 30532630535320256 |
oct | 2740762375727055 |
9 | 446157608325325 |
10 | 103421000003117 |
11 | 2aa5366635a425 |
12 | b723823792665 |
13 | 4592734bca514 |
14 | 1b77862d01b2d |
15 | be533e35a2b2 |
hex | 5e0f93f7ae2d |
103421000003117 has 2 divisors, whose sum is σ = 103421000003118. Its totient is φ = 103421000003116.
The previous prime is 103421000003107. The next prime is 103421000003171. The reversal of 103421000003117 is 711300000124301.
It is a happy number.
Together with next prime (103421000003171) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98963619218116 + 4457380785001 = 9948046^2 + 2111251^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103421000003117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 103421000003092 and 103421000003101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103421000003107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51710500001558 + 51710500001559.
It is an arithmetic number, because the mean of its divisors is an integer number (51710500001559).
Almost surely, 2103421000003117 is an apocalyptic number.
It is an amenable number.
103421000003117 is a deficient number, since it is larger than the sum of its proper divisors (1).
103421000003117 is an equidigital number, since it uses as much as digits as its factorization.
103421000003117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 103421000003117 its reverse (711300000124301), we get a palindrome (814721000127418).
The spelling of 103421000003117 in words is "one hundred three trillion, four hundred twenty-one billion, three thousand, one hundred seventeen".
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