Base | Representation |
---|---|
bin | 1001011010000111100100… |
… | …0011100011000110100111 |
3 | 1100121220110220102101202022 |
4 | 2112201321003203012213 |
5 | 2323440122412101434 |
6 | 34000040022533355 |
7 | 2115231462056621 |
oct | 226417103430647 |
9 | 40556426371668 |
10 | 10344312222119 |
11 | 3328aa8634697 |
12 | 11b096929725b |
13 | 5a0606547cb5 |
14 | 27a94b427c11 |
15 | 12e12c98422e |
hex | 968790e31a7 |
10344312222119 has 2 divisors, whose sum is σ = 10344312222120. Its totient is φ = 10344312222118.
The previous prime is 10344312222077. The next prime is 10344312222121. The reversal of 10344312222119 is 91122221344301.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10344312222119 is a prime.
It is a super-2 number, since 2×103443122221192 (a number of 27 digits) contains 22 as substring.
Together with 10344312222121, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10344312222719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5172156111059 + 5172156111060.
It is an arithmetic number, because the mean of its divisors is an integer number (5172156111060).
Almost surely, 210344312222119 is an apocalyptic number.
10344312222119 is a deficient number, since it is larger than the sum of its proper divisors (1).
10344312222119 is an equidigital number, since it uses as much as digits as its factorization.
10344312222119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 35.
The spelling of 10344312222119 in words is "ten trillion, three hundred forty-four billion, three hundred twelve million, two hundred twenty-two thousand, one hundred nineteen".
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