Base | Representation |
---|---|
bin | 1001011010010001011000… |
… | …1011100110001001111011 |
3 | 1100122011021121202210210201 |
4 | 2112210112023212021323 |
5 | 2324011022234322213 |
6 | 34001153352223031 |
7 | 2115354011610403 |
oct | 226442613461173 |
9 | 40564247683721 |
10 | 10346948354683 |
11 | 332a130669046 |
12 | 11b138409aa77 |
13 | 5a093672c355 |
14 | 27ab1b593803 |
15 | 12e2341006dd |
hex | 969162e627b |
10346948354683 has 2 divisors, whose sum is σ = 10346948354684. Its totient is φ = 10346948354682.
The previous prime is 10346948354681. The next prime is 10346948354737. The reversal of 10346948354683 is 38645384964301.
10346948354683 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10346948354683 - 21 = 10346948354681 is a prime.
Together with 10346948354681, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10346948354681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5173474177341 + 5173474177342.
It is an arithmetic number, because the mean of its divisors is an integer number (5173474177342).
Almost surely, 210346948354683 is an apocalyptic number.
10346948354683 is a deficient number, since it is larger than the sum of its proper divisors (1).
10346948354683 is an equidigital number, since it uses as much as digits as its factorization.
10346948354683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 179159040, while the sum is 64.
The spelling of 10346948354683 in words is "ten trillion, three hundred forty-six billion, nine hundred forty-eight million, three hundred fifty-four thousand, six hundred eighty-three".
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