Base | Representation |
---|---|
bin | 10011010010011010… |
… | …10110011101000001 |
3 | 222201122211122100021 |
4 | 21221031112131001 |
5 | 132201342321423 |
6 | 4431304253441 |
7 | 514415256103 |
oct | 115115263501 |
9 | 28648748307 |
10 | 10355042113 |
11 | 4434173449 |
12 | 200ba71281 |
13 | c9041a670 |
14 | 703383573 |
15 | 40914095d |
hex | 269356741 |
10355042113 has 16 divisors (see below), whose sum is σ = 11318985216. Its totient is φ = 9416085120.
The previous prime is 10355042101. The next prime is 10355042143. The reversal of 10355042113 is 31124055301.
It is a happy number.
It is not a de Polignac number, because 10355042113 - 213 = 10355033921 is a prime.
It is a super-3 number, since 3×103550421133 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10355042143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 211120 + ... + 255502.
It is an arithmetic number, because the mean of its divisors is an integer number (707436576).
Almost surely, 210355042113 is an apocalyptic number.
10355042113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10355042113 is a deficient number, since it is larger than the sum of its proper divisors (963943103).
10355042113 is a wasteful number, since it uses less digits than its factorization.
10355042113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44664.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 10355042113 its reverse (31124055301), we get a palindrome (41479097414).
The spelling of 10355042113 in words is "ten billion, three hundred fifty-five million, forty-two thousand, one hundred thirteen".
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