10355711025 has 24 divisors (see below), whose sum is σ = 18677938464. Its totient is φ = 5020950400.

The previous prime is 10355710993. The next prime is 10355711039. The reversal of 10355711025 is 52011755301.

It is not a de Polignac number, because 10355711025 - 2⁵ = 10355710993 is a prime.

It is a super-3 number, since 3×10355711025³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10355710983 and 10355711001.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6275364 + ... + 6277013.

It is an arithmetic number, because the mean of its divisors is an integer number (778247436).

Almost surely, 2^10355711025 is an apocalyptic number.

10355711025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

10355711025 is a deficient number, since it is larger than the sum of its proper divisors (8322227439).

10355711025 is a wasteful number, since it uses less digits than its factorization.

10355711025 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12552401 (or 12552396 counting only the distinct ones).

The product of its (nonzero) digits is 5250, while the sum is 30.

The spelling of 10355711025 in words is "ten billion, three hundred fifty-five million, seven hundred eleven thousand, twenty-five".