104012131 has 2 divisors, whose sum is σ = 104012132. Its totient is φ = 104012130.

The previous prime is 104012113. The next prime is 104012149. The reversal of 104012131 is 131210401.

Together with previous prime (104012113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (104012113) and next prime (104012149).

It is a cyclic number.

It is not a de Polignac number, because 104012131 - 2⁹ = 104011619 is a prime.

It is a super-2 number, since 2×104012131² = 21637046790322322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (104012101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52006065 + 52006066.

It is an arithmetic number, because the mean of its divisors is an integer number (52006066).

Almost surely, 2^104012131 is an apocalyptic number.

104012131 is a deficient number, since it is larger than the sum of its proper divisors (1).

104012131 is an equidigital number, since it uses as much as digits as its factorization.

104012131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 104012131 is about 10198.6337810513. The cubic root of 104012131 is about 470.2852214750.

Adding to 104012131 its reverse (131210401), we get a palindrome (235222532).

The spelling of 104012131 in words is "one hundred four million, twelve thousand, one hundred thirty-one".