10401447137 has 2 divisors, whose sum is σ = 10401447138. Its totient is φ = 10401447136.

The previous prime is 10401447109. The next prime is 10401447151. The reversal of 10401447137 is 73174410401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8613510481 + 1787936656 = 92809^2 + 42284^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10401447137 is a prime.

It is a super-3 number, since 3×10401447137³ (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10401447737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200723568 + 5200723569.

It is an arithmetic number, because the mean of its divisors is an integer number (5200723569).

Almost surely, 2^10401447137 is an apocalyptic number.

It is an amenable number.

10401447137 is a deficient number, since it is larger than the sum of its proper divisors (1).

10401447137 is an equidigital number, since it uses as much as digits as its factorization.

10401447137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9408, while the sum is 32.

Adding to 10401447137 its reverse (73174410401), we get a palindrome (83575857538).

It can be divided in two parts, 104014 and 47137, that added together give a palindrome (151151).

The spelling of 10401447137 in words is "ten billion, four hundred one million, four hundred forty-seven thousand, one hundred thirty-seven".