Base | Representation |
---|---|
bin | 10011010111111100… |
… | …10111110011101111 |
3 | 222211220011021002101 |
4 | 21223332113303233 |
5 | 132300232302101 |
6 | 4440043035531 |
7 | 515520561544 |
oct | 115376276357 |
9 | 28756137071 |
10 | 10401447151 |
11 | 4458389217 |
12 | 202350bba7 |
13 | c99c17674 |
14 | 7095c2bcb |
15 | 40d25a401 |
hex | 26bf97cef |
10401447151 has 2 divisors, whose sum is σ = 10401447152. Its totient is φ = 10401447150.
The previous prime is 10401447137. The next prime is 10401447169. The reversal of 10401447151 is 15174410401.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10401447151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10401447181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200723575 + 5200723576.
It is an arithmetic number, because the mean of its divisors is an integer number (5200723576).
Almost surely, 210401447151 is an apocalyptic number.
10401447151 is a deficient number, since it is larger than the sum of its proper divisors (1).
10401447151 is an equidigital number, since it uses as much as digits as its factorization.
10401447151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2240, while the sum is 28.
Adding to 10401447151 its reverse (15174410401), we get a palindrome (25575857552).
The spelling of 10401447151 in words is "ten billion, four hundred one million, four hundred forty-seven thousand, one hundred fifty-one".
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