Base | Representation |
---|---|
bin | 1001011101011111101111… |
… | …0010011000101011110101 |
3 | 1100211110020222010200120021 |
4 | 2113113323302120223311 |
5 | 2330412443032110031 |
6 | 34042434042005141 |
7 | 2122354454025514 |
oct | 227277362305365 |
9 | 40743228120507 |
10 | 10402340113141 |
11 | 3350675895019 |
12 | 12000627a67b1 |
13 | 5a5c23544ba2 |
14 | 27d69400267b |
15 | 1308c6ed3511 |
hex | 975fbc98af5 |
10402340113141 has 2 divisors, whose sum is σ = 10402340113142. Its totient is φ = 10402340113140.
The previous prime is 10402340113117. The next prime is 10402340113147. The reversal of 10402340113141 is 14131104320401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9926778161041 + 475561952100 = 3150679^2 + 689610^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10402340113141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10402340113147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5201170056570 + 5201170056571.
It is an arithmetic number, because the mean of its divisors is an integer number (5201170056571).
Almost surely, 210402340113141 is an apocalyptic number.
It is an amenable number.
10402340113141 is a deficient number, since it is larger than the sum of its proper divisors (1).
10402340113141 is an equidigital number, since it uses as much as digits as its factorization.
10402340113141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 10402340113141 its reverse (14131104320401), we get a palindrome (24533444433542).
The spelling of 10402340113141 in words is "ten trillion, four hundred two billion, three hundred forty million, one hundred thirteen thousand, one hundred forty-one".
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