Base | Representation |
---|---|
bin | 1001011101101010001110… |
… | …0101100001010111100111 |
3 | 1100211201112011102122221102 |
4 | 2113122203211201113213 |
5 | 2330434224230010002 |
6 | 34044021245310315 |
7 | 2122514306601611 |
oct | 227324345412747 |
9 | 40751464378842 |
10 | 10405155313127 |
11 | 335188aa04483 |
12 | 120070956539b |
13 | 5a62818647b3 |
14 | 27d87dc61db1 |
15 | 1309de221a02 |
hex | 976a39615e7 |
10405155313127 has 2 divisors, whose sum is σ = 10405155313128. Its totient is φ = 10405155313126.
The previous prime is 10405155313097. The next prime is 10405155313141. The reversal of 10405155313127 is 72131355150401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10405155313127 - 214 = 10405155296743 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10405155313177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5202577656563 + 5202577656564.
It is an arithmetic number, because the mean of its divisors is an integer number (5202577656564).
Almost surely, 210405155313127 is an apocalyptic number.
10405155313127 is a deficient number, since it is larger than the sum of its proper divisors (1).
10405155313127 is an equidigital number, since it uses as much as digits as its factorization.
10405155313127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63000, while the sum is 38.
The spelling of 10405155313127 in words is "ten trillion, four hundred five billion, one hundred fifty-five million, three hundred thirteen thousand, one hundred twenty-seven".
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