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10412022423431 is a prime number
BaseRepresentation
bin1001011110000011110011…
…1001011101111110000111
31100212101020202010000100002
42113200330321131332013
52331042310220022211
634051114515311515
72123146423223426
oct227407471357607
940771222100302
1010412022423431
113354794243052
121201b052ab59b
135a6b0747c885
1427dd31ca92bd
15130c9203b03b
hex9783ce5df87

10412022423431 has 2 divisors, whose sum is σ = 10412022423432. Its totient is φ = 10412022423430.

The previous prime is 10412022423427. The next prime is 10412022423433. The reversal of 10412022423431 is 13432422021401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10412022423431 - 22 = 10412022423427 is a prime.

It is a super-2 number, since 2×104120224234312 (a number of 27 digits) contains 22 as substring.

Together with 10412022423433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10412022423394 and 10412022423403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10412022423433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206011211715 + 5206011211716.

It is an arithmetic number, because the mean of its divisors is an integer number (5206011211716).

Almost surely, 210412022423431 is an apocalyptic number.

10412022423431 is a deficient number, since it is larger than the sum of its proper divisors (1).

10412022423431 is an equidigital number, since it uses as much as digits as its factorization.

10412022423431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 10412022423431 its reverse (13432422021401), we get a palindrome (23844444444832).

The spelling of 10412022423431 in words is "ten trillion, four hundred twelve billion, twenty-two million, four hundred twenty-three thousand, four hundred thirty-one".