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10413024493 is a prime number
BaseRepresentation
bin10011011001010101…
…00010010011101101
3222212200221110012211
421230222202103231
5132311213240433
64441135130421
7516021150664
oct115452422355
928780843184
1010413024493
114463976473
122027373a11
13c9c43c171
1470ad57ddb
1540e2958cd
hex26caa24ed

10413024493 has 2 divisors, whose sum is σ = 10413024494. Its totient is φ = 10413024492.

The previous prime is 10413024491. The next prime is 10413024521. The reversal of 10413024493 is 39442031401.

10413024493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9077706729 + 1335317764 = 95277^2 + 36542^2 .

It is a cyclic number.

It is not a de Polignac number, because 10413024493 - 21 = 10413024491 is a prime.

Together with 10413024491, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10413024491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206512246 + 5206512247.

It is an arithmetic number, because the mean of its divisors is an integer number (5206512247).

Almost surely, 210413024493 is an apocalyptic number.

It is an amenable number.

10413024493 is a deficient number, since it is larger than the sum of its proper divisors (1).

10413024493 is an equidigital number, since it uses as much as digits as its factorization.

10413024493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 10413024493 its reverse (39442031401), we get a palindrome (49855055894).

The spelling of 10413024493 in words is "ten billion, four hundred thirteen million, twenty-four thousand, four hundred ninety-three".