Base | Representation |
---|---|
bin | 1001011110100010000011… |
… | …0100010000110101111011 |
3 | 1100220011012120002012020121 |
4 | 2113220200310100311323 |
5 | 2331210422123401413 |
6 | 34054540301434111 |
7 | 2123554546031644 |
oct | 227504064206573 |
9 | 40804176065217 |
10 | 10420141231483 |
11 | 3358180088775 |
12 | 12035b026b937 |
13 | 5a77cc4c01c9 |
14 | 2804a225c6cb |
15 | 1310b9ba3b8d |
hex | 97a20d10d7b |
10420141231483 has 2 divisors, whose sum is σ = 10420141231484. Its totient is φ = 10420141231482.
The previous prime is 10420141231481. The next prime is 10420141231529. The reversal of 10420141231483 is 38413214102401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10420141231483 - 21 = 10420141231481 is a prime.
Together with 10420141231481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10420141231481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5210070615741 + 5210070615742.
It is an arithmetic number, because the mean of its divisors is an integer number (5210070615742).
Almost surely, 210420141231483 is an apocalyptic number.
10420141231483 is a deficient number, since it is larger than the sum of its proper divisors (1).
10420141231483 is an equidigital number, since it uses as much as digits as its factorization.
10420141231483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 34.
Adding to 10420141231483 its reverse (38413214102401), we get a palindrome (48833355333884).
The spelling of 10420141231483 in words is "ten trillion, four hundred twenty billion, one hundred forty-one million, two hundred thirty-one thousand, four hundred eighty-three".
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