Base | Representation |
---|---|
bin | 11110010101010101111… |
… | …01011100100011111011 |
3 | 10200122020012212001212021 |
4 | 33022222331130203323 |
5 | 114034012040220443 |
6 | 2114445253255311 |
7 | 135204635355625 |
oct | 17125275344373 |
9 | 3618205761767 |
10 | 1042250320123 |
11 | 37201a152831 |
12 | 149bb3634537 |
13 | 7738c61a76c |
14 | 3863382dc15 |
15 | 1c1a0aa99ed |
hex | f2aaf5c8fb |
1042250320123 has 2 divisors, whose sum is σ = 1042250320124. Its totient is φ = 1042250320122.
The previous prime is 1042250320121. The next prime is 1042250320183. The reversal of 1042250320123 is 3210230522401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1042250320123 - 21 = 1042250320121 is a prime.
It is a super-3 number, since 3×10422503201233 (a number of 37 digits) contains 333 as substring.
Together with 1042250320121, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1042250320121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521125160061 + 521125160062.
It is an arithmetic number, because the mean of its divisors is an integer number (521125160062).
Almost surely, 21042250320123 is an apocalyptic number.
1042250320123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1042250320123 is an equidigital number, since it uses as much as digits as its factorization.
1042250320123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 1042250320123 its reverse (3210230522401), we get a palindrome (4252480842524).
The spelling of 1042250320123 in words is "one trillion, forty-two billion, two hundred fifty million, three hundred twenty thousand, one hundred twenty-three".
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