Base | Representation |
---|---|
bin | 11110010101100111111… |
… | …01011100000100101011 |
3 | 10200122121201222022020112 |
4 | 33022303331130010223 |
5 | 114034314214004232 |
6 | 2114512245444535 |
7 | 135211450652402 |
oct | 17126375340453 |
9 | 3618551868215 |
10 | 1042401313067 |
11 | 372097402a94 |
12 | 14a03611074b |
13 | 773b49a65ba |
14 | 386498d6639 |
15 | 1c1ade834b2 |
hex | f2b3f5c12b |
1042401313067 has 2 divisors, whose sum is σ = 1042401313068. Its totient is φ = 1042401313066.
The previous prime is 1042401313061. The next prime is 1042401313069. The reversal of 1042401313067 is 7603131042401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1042401313067 - 220 = 1042400264491 is a prime.
Together with 1042401313069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1042401313061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521200656533 + 521200656534.
It is an arithmetic number, because the mean of its divisors is an integer number (521200656534).
Almost surely, 21042401313067 is an apocalyptic number.
1042401313067 is a deficient number, since it is larger than the sum of its proper divisors (1).
1042401313067 is an equidigital number, since it uses as much as digits as its factorization.
1042401313067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 1042401313067 its reverse (7603131042401), we get a palindrome (8645532355468).
The spelling of 1042401313067 in words is "one trillion, forty-two billion, four hundred one million, three hundred thirteen thousand, sixty-seven".
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