1043300234231 has 2 divisors, whose sum is σ = 1043300234232. Its totient is φ = 1043300234230.

The previous prime is 1043300234213. The next prime is 1043300234233. The reversal of 1043300234231 is 1324320033401.

Together with previous prime (1043300234213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1043300234231 - 2¹⁰ = 1043300233207 is a prime.

It is a super-2 number, since 2×1043300234231² (a number of 25 digits) contains 22 as substring.

Together with 1043300234233, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1043300234231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1043300234233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521650117115 + 521650117116.

It is an arithmetic number, because the mean of its divisors is an integer number (521650117116).

Almost surely, 2^{1043300234231} is an apocalyptic number.

1043300234231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1043300234231 is an equidigital number, since it uses as much as digits as its factorization.

1043300234231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 1043300234231 its reverse (1324320033401), we get a palindrome (2367620267632).

The spelling of 1043300234231 in words is "one trillion, forty-three billion, three hundred million, two hundred thirty-four thousand, two hundred thirty-one".