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104333331299453 is a prime number
BaseRepresentation
bin10111101110001111111111…
…001001100111110001111101
3111200102011120020122201002022
4113232033333021213301331
5102133344130303040303
61005522023135205525
730655556132352134
oct2756177711476175
9450364506581068
10104333331299453
1130275576610713
12b8505b96768a5
13462a78b355c79
141ba9a8dd0491b
15c0de39249438
hex5ee3ff267c7d

104333331299453 has 2 divisors, whose sum is σ = 104333331299454. Its totient is φ = 104333331299452.

The previous prime is 104333331299437. The next prime is 104333331299479. The reversal of 104333331299453 is 354992133333401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96769362728164 + 7563968571289 = 9837142^2 + 2750267^2 .

It is a cyclic number.

It is not a de Polignac number, because 104333331299453 - 24 = 104333331299437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 104333331299395 and 104333331299404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (104333331293453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52166665649726 + 52166665649727.

It is an arithmetic number, because the mean of its divisors is an integer number (52166665649727).

Almost surely, 2104333331299453 is an apocalyptic number.

It is an amenable number.

104333331299453 is a deficient number, since it is larger than the sum of its proper divisors (1).

104333331299453 is an equidigital number, since it uses as much as digits as its factorization.

104333331299453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9447840, while the sum is 53.

The spelling of 104333331299453 in words is "one hundred four trillion, three hundred thirty-three billion, three hundred thirty-one million, two hundred ninety-nine thousand, four hundred fifty-three".