Base | Representation |
---|---|
bin | 10011011011110110… |
… | …00000111011110001 |
3 | 222221011122021210212 |
4 | 21231323000323301 |
5 | 132332113341312 |
6 | 4443211233505 |
7 | 516365366114 |
oct | 115573007361 |
9 | 28834567725 |
10 | 10434121457 |
11 | 4474875981 |
12 | 2032448895 |
13 | ca3917986 |
14 | 70da8a57b |
15 | 411061822 |
hex | 26dec0ef1 |
10434121457 has 2 divisors, whose sum is σ = 10434121458. Its totient is φ = 10434121456.
The previous prime is 10434121427. The next prime is 10434121459. The reversal of 10434121457 is 75412143401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8388911281 + 2045210176 = 91591^2 + 45224^2 .
It is a cyclic number.
It is not a de Polignac number, because 10434121457 - 26 = 10434121393 is a prime.
Together with 10434121459, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10434121459) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5217060728 + 5217060729.
It is an arithmetic number, because the mean of its divisors is an integer number (5217060729).
Almost surely, 210434121457 is an apocalyptic number.
It is an amenable number.
10434121457 is a deficient number, since it is larger than the sum of its proper divisors (1).
10434121457 is an equidigital number, since it uses as much as digits as its factorization.
10434121457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 10434121457 its reverse (75412143401), we get a palindrome (85846264858).
The spelling of 10434121457 in words is "ten billion, four hundred thirty-four million, one hundred twenty-one thousand, four hundred fifty-seven".
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