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104342555413 is a prime number
BaseRepresentation
bin110000100101101001…
…1010000101100010101
3100222022210221000101101
41201023103100230111
53202143143233123
6115533451030101
710352464041625
oct1411323205425
9328283830341
10104342555413
114028471a278
121828013b331
139abb3ab965
14509baa4885
152aaa5c7aad
hex184b4d0b15

104342555413 has 2 divisors, whose sum is σ = 104342555414. Its totient is φ = 104342555412.

The previous prime is 104342555411. The next prime is 104342555419. The reversal of 104342555413 is 314555243401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87792504804 + 16550050609 = 296298^2 + 128647^2 .

It is a cyclic number.

It is not a de Polignac number, because 104342555413 - 21 = 104342555411 is a prime.

It is a super-2 number, since 2×1043425554132 (a number of 23 digits) contains 22 as substring.

Together with 104342555411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (104342555411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52171277706 + 52171277707.

It is an arithmetic number, because the mean of its divisors is an integer number (52171277707).

Almost surely, 2104342555413 is an apocalyptic number.

It is an amenable number.

104342555413 is a deficient number, since it is larger than the sum of its proper divisors (1).

104342555413 is an equidigital number, since it uses as much as digits as its factorization.

104342555413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 104342555413 its reverse (314555243401), we get a palindrome (418897798814).

The spelling of 104342555413 in words is "one hundred four billion, three hundred forty-two million, five hundred fifty-five thousand, four hundred thirteen".