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1043425554131 is a prime number
BaseRepresentation
bin11110010111100010000…
…00100110111011010011
310200202021010021010211202
433023301000212323103
5114043413420213011
62115202034501415
7135246025605062
oct17136100467323
93622233233752
101043425554131
11372572583504
1214a28113486b
1377518c503bc
14387059541d9
151c21dd5223b
hexf2f1026ed3

1043425554131 has 2 divisors, whose sum is σ = 1043425554132. Its totient is φ = 1043425554130.

The previous prime is 1043425554091. The next prime is 1043425554137. The reversal of 1043425554131 is 1314555243401.

It is a strong prime.

It is an emirp because it is prime and its reverse (1314555243401) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1043425554131 is a prime.

It is a super-2 number, since 2×10434255541312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1043425554137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521712777065 + 521712777066.

It is an arithmetic number, because the mean of its divisors is an integer number (521712777066).

Almost surely, 21043425554131 is an apocalyptic number.

1043425554131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1043425554131 is an equidigital number, since it uses as much as digits as its factorization.

1043425554131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 38.

The spelling of 1043425554131 in words is "one trillion, forty-three billion, four hundred twenty-five million, five hundred fifty-four thousand, one hundred thirty-one".