1314555243401 has 2 divisors, whose sum is σ = 1314555243402. Its totient is φ = 1314555243400.

The previous prime is 1314555243389. The next prime is 1314555243403. The reversal of 1314555243401 is 1043425554131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 819468510025 + 495086733376 = 905245^2 + 703624^2 .

It is an emirp because it is prime and its reverse (1043425554131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1314555243401 - 2¹⁴ = 1314555227017 is a prime.

Together with 1314555243403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1314555243403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657277621700 + 657277621701.

It is an arithmetic number, because the mean of its divisors is an integer number (657277621701).

Almost surely, 2^{1314555243401} is an apocalyptic number.

It is an amenable number.

1314555243401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314555243401 is an equidigital number, since it uses as much as digits as its factorization.

1314555243401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 38.

The spelling of 1314555243401 in words is "one trillion, three hundred fourteen billion, five hundred fifty-five million, two hundred forty-three thousand, four hundred one".