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1043443540213 is a prime number
BaseRepresentation
bin11110010111100100001…
…01001110000011110101
310200202022101002221002221
433023302011032003311
5114043433021241323
62115203520202341
7135246334515454
oct17136205160365
93622271087087
101043443540213
11372581748738
1214a2871693b1
137751c8a9c59
14387080b6b9b
151c22070655d
hexf2f214e0f5

1043443540213 has 2 divisors, whose sum is σ = 1043443540214. Its totient is φ = 1043443540212.

The previous prime is 1043443540193. The next prime is 1043443540219. The reversal of 1043443540213 is 3120453443401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1034862667524 + 8580872689 = 1017282^2 + 92633^2 .

It is a cyclic number.

It is not a de Polignac number, because 1043443540213 - 221 = 1043441443061 is a prime.

It is a super-2 number, since 2×10434435402132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1043443540219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521721770106 + 521721770107.

It is an arithmetic number, because the mean of its divisors is an integer number (521721770107).

Almost surely, 21043443540213 is an apocalyptic number.

It is an amenable number.

1043443540213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1043443540213 is an equidigital number, since it uses as much as digits as its factorization.

1043443540213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 34.

Adding to 1043443540213 its reverse (3120453443401), we get a palindrome (4163896983614).

The spelling of 1043443540213 in words is "one trillion, forty-three billion, four hundred forty-three million, five hundred forty thousand, two hundred thirteen".