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10440015431 is a prime number
BaseRepresentation
bin10011011100100010…
…11111111001000111
3222221120201201211012
421232101133321013
5132340120443211
64443541432435
7516466444526
oct115621377107
928846651735
1010440015431
11447813112a
12203440b71b
13ca4bcc631
147107824bd
15411827d8b
hex26e45fe47

10440015431 has 2 divisors, whose sum is σ = 10440015432. Its totient is φ = 10440015430.

The previous prime is 10440015409. The next prime is 10440015433. The reversal of 10440015431 is 13451004401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10440015431 - 210 = 10440014407 is a prime.

It is a super-2 number, since 2×104400154312 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 10440015433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10440015397 and 10440015406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10440015433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5220007715 + 5220007716.

It is an arithmetic number, because the mean of its divisors is an integer number (5220007716).

Almost surely, 210440015431 is an apocalyptic number.

10440015431 is a deficient number, since it is larger than the sum of its proper divisors (1).

10440015431 is an equidigital number, since it uses as much as digits as its factorization.

10440015431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 10440015431 its reverse (13451004401), we get a palindrome (23891019832).

The spelling of 10440015431 in words is "ten billion, four hundred forty million, fifteen thousand, four hundred thirty-one".