Base | Representation |
---|---|
bin | 10011011100110011… |
… | …00000000101000111 |
3 | 222221201200022121221 |
4 | 21232121200011013 |
5 | 132341140111401 |
6 | 4444054421211 |
7 | 516523333105 |
oct | 115631400507 |
9 | 28851608557 |
10 | 10442113351 |
11 | 447933434a |
12 | 2035061807 |
13 | ca54854c7 |
14 | 710b6ac75 |
15 | 411ade7a1 |
hex | 26e660147 |
10442113351 has 2 divisors, whose sum is σ = 10442113352. Its totient is φ = 10442113350.
The previous prime is 10442113267. The next prime is 10442113387. The reversal of 10442113351 is 15331124401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10442113351 - 213 = 10442105159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10442113051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5221056675 + 5221056676.
It is an arithmetic number, because the mean of its divisors is an integer number (5221056676).
Almost surely, 210442113351 is an apocalyptic number.
10442113351 is a deficient number, since it is larger than the sum of its proper divisors (1).
10442113351 is an equidigital number, since it uses as much as digits as its factorization.
10442113351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 10442113351 its reverse (15331124401), we get a palindrome (25773237752).
The spelling of 10442113351 in words is "ten billion, four hundred forty-two million, one hundred thirteen thousand, three hundred fifty-one".
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