104444012131 has 2 divisors, whose sum is σ = 104444012132. Its totient is φ = 104444012130.

The previous prime is 104444012129. The next prime is 104444012159. The reversal of 104444012131 is 131210444401.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 104444012131 - 2¹ = 104444012129 is a prime.

It is a super-2 number, since 2×104444012131² (a number of 23 digits) contains 22 as substring.

Together with 104444012129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 104444012096 and 104444012105.

It is not a weakly prime, because it can be changed into another prime (104444012831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52222006065 + 52222006066.

It is an arithmetic number, because the mean of its divisors is an integer number (52222006066).

Almost surely, 2^104444012131 is an apocalyptic number.

104444012131 is a deficient number, since it is larger than the sum of its proper divisors (1).

104444012131 is an equidigital number, since it uses as much as digits as its factorization.

104444012131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 104444012131 its reverse (131210444401), we get a palindrome (235654456532).

The spelling of 104444012131 in words is "one hundred four billion, four hundred forty-four million, twelve thousand, one hundred thirty-one".