1049081496137 has 2 divisors, whose sum is σ = 1049081496138. Its totient is φ = 1049081496136.

The previous prime is 1049081496121. The next prime is 1049081496139. The reversal of 1049081496137 is 7316941809401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1048649729296 + 431766841 = 1024036^2 + 20779^2 .

It is a cyclic number.

It is not a de Polignac number, because 1049081496137 - 2⁴ = 1049081496121 is a prime.

It is a super-2 number, since 2×1049081496137² (a number of 25 digits) contains 22 as substring.

Together with 1049081496139, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1049081496139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 524540748068 + 524540748069.

It is an arithmetic number, because the mean of its divisors is an integer number (524540748069).

Almost surely, 2^{1049081496137} is an apocalyptic number.

It is an amenable number.

1049081496137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1049081496137 is an equidigital number, since it uses as much as digits as its factorization.

1049081496137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1306368, while the sum is 53.

The spelling of 1049081496137 in words is "one trillion, forty-nine billion, eighty-one million, four hundred ninety-six thousand, one hundred thirty-seven".