1049140031 has 2 divisors, whose sum is σ = 1049140032. Its totient is φ = 1049140030.

The previous prime is 1049139977. The next prime is 1049140033. The reversal of 1049140031 is 1300419401.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1049140031 is a prime.

It is a super-2 number, since 2×1049140031² = 2201389609293361922, which contains 22 as substring.

Together with 1049140033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1049139979 and 1049140006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1049140033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 524570015 + 524570016.

It is an arithmetic number, because the mean of its divisors is an integer number (524570016).

Almost surely, 2^1049140031 is an apocalyptic number.

1049140031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1049140031 is an equidigital number, since it uses as much as digits as its factorization.

1049140031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

The square root of 1049140031 is about 32390.4311641571. The cubic root of 1049140031 is about 1016.1187986900.

Adding to 1049140031 its reverse (1300419401), we get a palindrome (2349559432).

The spelling of 1049140031 in words is "one billion, forty-nine million, one hundred forty thousand, thirty-one".