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1049714207 is a prime number
BaseRepresentation
bin111110100100010…
…101111000011111
32201011020000011222
4332210111320133
54122211323312
6252055003555
735004265163
oct7644257037
92634200158
101049714207
11499599903
122536695bb
13139625489
149d5acca3
1562251672
hex3e915e1f

1049714207 has 2 divisors, whose sum is σ = 1049714208. Its totient is φ = 1049714206.

The previous prime is 1049714203. The next prime is 1049714209. The reversal of 1049714207 is 7024179401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1049714207 - 22 = 1049714203 is a prime.

It is a super-2 number, since 2×10497142072 = 2203799832755277698, which contains 22 as substring.

Together with 1049714209, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1049714201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 524857103 + 524857104.

It is an arithmetic number, because the mean of its divisors is an integer number (524857104).

Almost surely, 21049714207 is an apocalyptic number.

1049714207 is a deficient number, since it is larger than the sum of its proper divisors (1).

1049714207 is an equidigital number, since it uses as much as digits as its factorization.

1049714207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14112, while the sum is 35.

The square root of 1049714207 is about 32399.2933101943. The cubic root of 1049714207 is about 1016.3041329029.

The spelling of 1049714207 in words is "one billion, forty-nine million, seven hundred fourteen thousand, two hundred seven".