10501251221 has 2 divisors, whose sum is σ = 10501251222. Its totient is φ = 10501251220.

The previous prime is 10501251181. The next prime is 10501251223. The reversal of 10501251221 is 12215210501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6180160996 + 4321090225 = 78614^2 + 65735^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10501251221 is a prime.

It is a super-2 number, since 2×10501251221² (a number of 21 digits) contains 22 as substring.

Together with 10501251223, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10501251193 and 10501251202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10501251223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5250625610 + 5250625611.

It is an arithmetic number, because the mean of its divisors is an integer number (5250625611).

Almost surely, 2^10501251221 is an apocalyptic number.

It is an amenable number.

10501251221 is a deficient number, since it is larger than the sum of its proper divisors (1).

10501251221 is an equidigital number, since it uses as much as digits as its factorization.

10501251221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 200, while the sum is 20.

Adding to 10501251221 its reverse (12215210501), we get a palindrome (22716461722).

The spelling of 10501251221 in words is "ten billion, five hundred one million, two hundred fifty-one thousand, two hundred twenty-one".