Base | Representation |
---|---|
bin | 10111111000110000000110… |
… | …100011110010100010011111 |
3 | 111202222011100021122120000211 |
4 | 113320300012203302202133 |
5 | 102232210130041334003 |
6 | 1011233334432433251 |
7 | 31061655041113633 |
oct | 2770600643624237 |
9 | 452864307576024 |
10 | 105055010105503 |
11 | 30523641476147 |
12 | b9484463a8827 |
13 | 468084cc363a3 |
14 | 1bd299245adc3 |
15 | c22ac663696d |
hex | 5f8c068f289f |
105055010105503 has 2 divisors, whose sum is σ = 105055010105504. Its totient is φ = 105055010105502.
The previous prime is 105055010105501. The next prime is 105055010105659. The reversal of 105055010105503 is 305501010550501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 105055010105503 - 21 = 105055010105501 is a prime.
It is a super-2 number, since 2×1050550101055032 (a number of 29 digits) contains 22 as substring.
Together with 105055010105501, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (105055010105501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52527505052751 + 52527505052752.
It is an arithmetic number, because the mean of its divisors is an integer number (52527505052752).
Almost surely, 2105055010105503 is an apocalyptic number.
105055010105503 is a deficient number, since it is larger than the sum of its proper divisors (1).
105055010105503 is an equidigital number, since it uses as much as digits as its factorization.
105055010105503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9375, while the sum is 31.
The spelling of 105055010105503 in words is "one hundred five trillion, fifty-five billion, ten million, one hundred five thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.247 sec. • engine limits •