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1051040314213 is a prime number
BaseRepresentation
bin11110100101101101110…
…00100111001101100101
310201110220210210000220221
433102312320213031211
5114210012310023323
62122501413324341
7135635521156561
oct17226670471545
93643823700827
101051040314213
1137581a94745a
1214b8473366b1
137816071c2b6
1438c28dba6a1
151c51760255d
hexf4b6e27365

1051040314213 has 2 divisors, whose sum is σ = 1051040314214. Its totient is φ = 1051040314212.

The previous prime is 1051040314201. The next prime is 1051040314351. The reversal of 1051040314213 is 3124130401501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 617698539844 + 433341774369 = 785938^2 + 658287^2 .

It is a cyclic number.

It is not a de Polignac number, because 1051040314213 - 213 = 1051040306021 is a prime.

It is a super-2 number, since 2×10510403142132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1051040314813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525520157106 + 525520157107.

It is an arithmetic number, because the mean of its divisors is an integer number (525520157107).

Almost surely, 21051040314213 is an apocalyptic number.

It is an amenable number.

1051040314213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1051040314213 is an equidigital number, since it uses as much as digits as its factorization.

1051040314213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1051040314213 its reverse (3124130401501), we get a palindrome (4175170715714).

The spelling of 1051040314213 in words is "one trillion, fifty-one billion, forty million, three hundred fourteen thousand, two hundred thirteen".