Search a number
-
+
1051231115437 is a prime number
BaseRepresentation
bin11110100110000100100…
…00011101100010101101
310201111102002210201222221
433103002100131202231
5114210410131143222
62122532351035341
7135643326022426
oct17230220354255
93644362721887
101051231115437
11375908617218
1214b89b20bb51
1378191105629
1438c4648664d
151c5292410c7
hexf4c241d8ad

1051231115437 has 2 divisors, whose sum is σ = 1051231115438. Its totient is φ = 1051231115436.

The previous prime is 1051231115413. The next prime is 1051231115489. The reversal of 1051231115437 is 7345111321501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 661263338761 + 389967776676 = 813181^2 + 624474^2 .

It is a cyclic number.

It is not a de Polignac number, because 1051231115437 - 215 = 1051231082669 is a prime.

It is a super-2 number, since 2×10512311154372 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1054231115437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525615557718 + 525615557719.

It is an arithmetic number, because the mean of its divisors is an integer number (525615557719).

Almost surely, 21051231115437 is an apocalyptic number.

It is an amenable number.

1051231115437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1051231115437 is an equidigital number, since it uses as much as digits as its factorization.

1051231115437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12600, while the sum is 34.

Adding to 1051231115437 its reverse (7345111321501), we get a palindrome (8396342436938).

The spelling of 1051231115437 in words is "one trillion, fifty-one billion, two hundred thirty-one million, one hundred fifteen thousand, four hundred thirty-seven".