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1051965347093 is a prime number
BaseRepresentation
bin11110100111011100000…
…01010101010100010101
310201120022021101120110222
433103232001111110111
5114213411112101333
62123133300124125
7136000452625463
oct17235601252425
93646267346428
101051965347093
11376155017341
1214ba65096645
137827a26bb2b
1438cb5bb1833
151c56d926298
hexf4ee055515

1051965347093 has 2 divisors, whose sum is σ = 1051965347094. Its totient is φ = 1051965347092.

The previous prime is 1051965347087. The next prime is 1051965347131. The reversal of 1051965347093 is 3907435691501.

1051965347093 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 998596492804 + 53368854289 = 999298^2 + 231017^2 .

It is a cyclic number.

It is not a de Polignac number, because 1051965347093 - 214 = 1051965330709 is a prime.

It is a super-2 number, since 2×10519653470932 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1051965347003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525982673546 + 525982673547.

It is an arithmetic number, because the mean of its divisors is an integer number (525982673547).

Almost surely, 21051965347093 is an apocalyptic number.

It is an amenable number.

1051965347093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1051965347093 is an equidigital number, since it uses as much as digits as its factorization.

1051965347093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3061800, while the sum is 53.

The spelling of 1051965347093 in words is "one trillion, fifty-one billion, nine hundred sixty-five million, three hundred forty-seven thousand, ninety-three".