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1052042342501 is a prime number
BaseRepresentation
bin11110100111100101001…
…11000011000001100101
310201120111122021100022202
433103302213003001211
5114214040314430001
62123145050304245
7136002406236053
oct17236247030145
93646448240282
101052042342501
11376194526107
1214ba86a28085
13782901b9747
1438cc20d51d3
151c57558496b
hexf4f29c3065

1052042342501 has 2 divisors, whose sum is σ = 1052042342502. Its totient is φ = 1052042342500.

The previous prime is 1052042342497. The next prime is 1052042342503. The reversal of 1052042342501 is 1052432402501.

1052042342501 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 865030204900 + 187012137601 = 930070^2 + 432449^2 .

It is a cyclic number.

It is not a de Polignac number, because 1052042342501 - 22 = 1052042342497 is a prime.

It is a super-2 number, since 2×10520423425012 (a number of 25 digits) contains 22 as substring.

Together with 1052042342503, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1052042342503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526021171250 + 526021171251.

It is an arithmetic number, because the mean of its divisors is an integer number (526021171251).

Almost surely, 21052042342501 is an apocalyptic number.

It is an amenable number.

1052042342501 is a deficient number, since it is larger than the sum of its proper divisors (1).

1052042342501 is an equidigital number, since it uses as much as digits as its factorization.

1052042342501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 29.

The spelling of 1052042342501 in words is "one trillion, fifty-two billion, forty-two million, three hundred forty-two thousand, five hundred one".