1052124433 has 2 divisors, whose sum is σ = 1052124434. Its totient is φ = 1052124432.

The previous prime is 1052124431. The next prime is 1052124467. The reversal of 1052124433 is 3344212501.

1052124433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1028035969 + 24088464 = 32063^2 + 4908^2 .

It is a cyclic number.

It is not a de Polignac number, because 1052124433 - 2¹ = 1052124431 is a prime.

It is a super-2 number, since 2×1052124433² = 2213931645031142978, which contains 22 as substring.

Together with 1052124431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1052124398 and 1052124407.

It is not a weakly prime, because it can be changed into another prime (1052124431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526062216 + 526062217.

It is an arithmetic number, because the mean of its divisors is an integer number (526062217).

Almost surely, 2^1052124433 is an apocalyptic number.

It is an amenable number.

1052124433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1052124433 is an equidigital number, since it uses as much as digits as its factorization.

1052124433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 1052124433 is about 32436.4676406048. The cubic root of 1052124433 is about 1017.0813762870.

Adding to 1052124433 its reverse (3344212501), we get a palindrome (4396336934).

The spelling of 1052124433 in words is "one billion, fifty-two million, one hundred twenty-four thousand, four hundred thirty-three".