105313441481 has 2 divisors, whose sum is σ = 105313441482. Its totient is φ = 105313441480.

The previous prime is 105313441439. The next prime is 105313441483. The reversal of 105313441481 is 184144313501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102714481081 + 2598960400 = 320491^2 + 50980^2 .

It is an emirp because it is prime and its reverse (184144313501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 105313441481 - 2¹⁰ = 105313440457 is a prime.

It is a super-2 number, since 2×105313441481² (a number of 23 digits) contains 22 as substring.

Together with 105313441483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (105313441483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52656720740 + 52656720741.

It is an arithmetic number, because the mean of its divisors is an integer number (52656720741).

Almost surely, 2^105313441481 is an apocalyptic number.

It is an amenable number.

105313441481 is a deficient number, since it is larger than the sum of its proper divisors (1).

105313441481 is an equidigital number, since it uses as much as digits as its factorization.

105313441481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 35.

Adding to 105313441481 its reverse (184144313501), we get a palindrome (289457754982).

The spelling of 105313441481 in words is "one hundred five billion, three hundred thirteen million, four hundred forty-one thousand, four hundred eighty-one".