Base | Representation |
---|---|
bin | 110001000010100101… |
… | …0111001011011001011 |
3 | 101001211110211010200201 |
4 | 1202011022321123023 |
5 | 3211140220111413 |
6 | 120214052313031 |
7 | 10415523324355 |
oct | 1420512713313 |
9 | 331743733621 |
10 | 105313441483 |
11 | 40732768358 |
12 | 184b1312777 |
13 | 9c14594263 |
14 | 51509d40d5 |
15 | 2b159579dd |
hex | 18852b96cb |
105313441483 has 2 divisors, whose sum is σ = 105313441484. Its totient is φ = 105313441482.
The previous prime is 105313441481. The next prime is 105313441501. The reversal of 105313441483 is 384144313501.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 105313441483 - 21 = 105313441481 is a prime.
It is a super-2 number, since 2×1053134414832 (a number of 23 digits) contains 22 as substring.
Together with 105313441481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (105313441481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52656720741 + 52656720742.
It is an arithmetic number, because the mean of its divisors is an integer number (52656720742).
Almost surely, 2105313441483 is an apocalyptic number.
105313441483 is a deficient number, since it is larger than the sum of its proper divisors (1).
105313441483 is an equidigital number, since it uses as much as digits as its factorization.
105313441483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 37.
Adding to 105313441483 its reverse (384144313501), we get a palindrome (489457754984).
The spelling of 105313441483 in words is "one hundred five billion, three hundred thirteen million, four hundred forty-one thousand, four hundred eighty-three".
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