Base | Representation |
---|---|
bin | 1001100101000100010000… |
… | …0111000111001110110111 |
3 | 1101021212222020111210022112 |
4 | 2121101010013013032313 |
5 | 2340030330021300421 |
6 | 34222304030521235 |
7 | 2134640516214125 |
oct | 231210407071667 |
9 | 41255866453275 |
10 | 10532402525111 |
11 | 33a0848712195 |
12 | 122130036621b |
13 | 5b528032c47c |
14 | 285ab18b6915 |
15 | 133e8a57445b |
hex | 994441c73b7 |
10532402525111 has 2 divisors, whose sum is σ = 10532402525112. Its totient is φ = 10532402525110.
The previous prime is 10532402525039. The next prime is 10532402525243. The reversal of 10532402525111 is 11152520423501.
It is a weak prime.
It is an emirp because it is prime and its reverse (11152520423501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10532402525111 - 210 = 10532402524087 is a prime.
It is a super-2 number, since 2×105324025251112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10532402522111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5266201262555 + 5266201262556.
It is an arithmetic number, because the mean of its divisors is an integer number (5266201262556).
Almost surely, 210532402525111 is an apocalyptic number.
10532402525111 is a deficient number, since it is larger than the sum of its proper divisors (1).
10532402525111 is an equidigital number, since it uses as much as digits as its factorization.
10532402525111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 10532402525111 its reverse (11152520423501), we get a palindrome (21684922948612).
The spelling of 10532402525111 in words is "ten trillion, five hundred thirty-two billion, four hundred two million, five hundred twenty-five thousand, one hundred eleven".
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