Base | Representation |
---|---|
bin | 11110101011010010101… |
… | …01000010011010110100 |
3 | 10201202122110010121212021 |
4 | 33111221111002122310 |
5 | 114232130213011012 |
6 | 2124114441002524 |
7 | 136102643052553 |
oct | 17255125023264 |
9 | 3652573117767 |
10 | 1054034110132 |
11 | 37701685a663 |
12 | 150341a83444 |
13 | 78519a40983 |
14 | 39030849d9a |
15 | 1c64036d007 |
hex | f5695426b4 |
1054034110132 has 24 divisors (see below), whose sum is σ = 1875388443264. Its totient is φ = 518280745152.
The previous prime is 1054034110111. The next prime is 1054034110147. The reversal of 1054034110132 is 2310114304501.
1054034110132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×10540341101322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1054034110097 and 1054034110106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8929308 + ... + 9046579.
It is an arithmetic number, because the mean of its divisors is an integer number (78141185136).
Almost surely, 21054034110132 is an apocalyptic number.
It is an amenable number.
1054034110132 is a deficient number, since it is larger than the sum of its proper divisors (821354333132).
1054034110132 is a wasteful number, since it uses less digits than its factorization.
1054034110132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17976135 (or 17976133 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1054034110132 its reverse (2310114304501), we get a palindrome (3364148414633).
The spelling of 1054034110132 in words is "one trillion, fifty-four billion, thirty-four million, one hundred ten thousand, one hundred thirty-two".
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