1054331405431 has 2 divisors, whose sum is σ = 1054331405432. Its totient is φ = 1054331405430.

The previous prime is 1054331405423. The next prime is 1054331405441. The reversal of 1054331405431 is 1345041334501.

It is a weak prime.

It is an emirp because it is prime and its reverse (1345041334501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1054331405431 - 2³ = 1054331405423 is a prime.

It is a super-3 number, since 3×1054331405431³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1054331405441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527165702715 + 527165702716.

It is an arithmetic number, because the mean of its divisors is an integer number (527165702716).

Almost surely, 2^{1054331405431} is an apocalyptic number.

1054331405431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1054331405431 is an equidigital number, since it uses as much as digits as its factorization.

1054331405431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 1054331405431 its reverse (1345041334501), we get a palindrome (2399372739932).

The spelling of 1054331405431 in words is "one trillion, fifty-four billion, three hundred thirty-one million, four hundred five thousand, four hundred thirty-one".