Base | Representation |
---|---|
bin | 11110101110011101101… |
… | …11001111001011100101 |
3 | 10201221001011111120010222 |
4 | 33113032313033023211 |
5 | 114244122304332432 |
6 | 2124555452054125 |
7 | 136163106213062 |
oct | 17271667171345 |
9 | 3657034446128 |
10 | 1055737574117 |
11 | 377810379336 |
12 | 150738464345 |
13 | 7872b930b25 |
14 | 39152b93c69 |
15 | 1c6deba8112 |
hex | f5cedcf2e5 |
1055737574117 has 2 divisors, whose sum is σ = 1055737574118. Its totient is φ = 1055737574116.
The previous prime is 1055737574041. The next prime is 1055737574123. The reversal of 1055737574117 is 7114757375501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 947057902561 + 108679671556 = 973169^2 + 329666^2 .
It is a cyclic number.
It is not a de Polignac number, because 1055737574117 - 226 = 1055670465253 is a prime.
It is a super-2 number, since 2×10557375741172 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1055737574917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527868787058 + 527868787059.
It is an arithmetic number, because the mean of its divisors is an integer number (527868787059).
Almost surely, 21055737574117 is an apocalyptic number.
It is an amenable number.
1055737574117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1055737574117 is an equidigital number, since it uses as much as digits as its factorization.
1055737574117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3601500, while the sum is 53.
The spelling of 1055737574117 in words is "one trillion, fifty-five billion, seven hundred thirty-seven million, five hundred seventy-four thousand, one hundred seventeen".
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