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105633131 is a prime number
BaseRepresentation
bin1100100101111…
…01010101101011
321100202201102012
412102331111223
5204020230011
614252030135
72421603212
oct622752553
9240681365
10105633131
115469980a
122b46234b
1318b66816
141005a079
159418a8b
hex64bd56b

105633131 has 2 divisors, whose sum is σ = 105633132. Its totient is φ = 105633130.

The previous prime is 105633127. The next prime is 105633133. The reversal of 105633131 is 131336501.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (131336501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 105633131 - 22 = 105633127 is a prime.

It is a super-2 number, since 2×1056331312 = 22316716729726322, which contains 22 as substring.

Together with 105633133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 105633097 and 105633106.

It is not a weakly prime, because it can be changed into another prime (105633133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52816565 + 52816566.

It is an arithmetic number, because the mean of its divisors is an integer number (52816566).

Almost surely, 2105633131 is an apocalyptic number.

105633131 is a deficient number, since it is larger than the sum of its proper divisors (1).

105633131 is an equidigital number, since it uses as much as digits as its factorization.

105633131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 810, while the sum is 23.

The square root of 105633131 is about 10277.7979645447. The cubic root of 105633131 is about 472.7157265436.

Adding to 105633131 its reverse (131336501), we get a palindrome (236969632).

The spelling of 105633131 in words is "one hundred five million, six hundred thirty-three thousand, one hundred thirty-one".