Base | Representation |
---|---|
bin | 10011101011011100… |
… | …11110111010110011 |
3 | 1000021022000100200011 |
4 | 21311232132322303 |
5 | 133114123213011 |
6 | 4504205435351 |
7 | 522545323042 |
oct | 116556367263 |
9 | 30238010604 |
10 | 10565054131 |
11 | 45317745a5 |
12 | 206a26bb57 |
13 | cc4a9bb28 |
14 | 723210559 |
15 | 41c7c6621 |
hex | 275b9eeb3 |
10565054131 has 2 divisors, whose sum is σ = 10565054132. Its totient is φ = 10565054130.
The previous prime is 10565054089. The next prime is 10565054173. The reversal of 10565054131 is 13145056501.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (10565054089) and next prime (10565054173).
It is a cyclic number.
It is not a de Polignac number, because 10565054131 - 29 = 10565053619 is a prime.
It is a super-2 number, since 2×105650541312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10565054093 and 10565054102.
It is not a weakly prime, because it can be changed into another prime (10565057131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5282527065 + 5282527066.
It is an arithmetic number, because the mean of its divisors is an integer number (5282527066).
Almost surely, 210565054131 is an apocalyptic number.
10565054131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10565054131 is an equidigital number, since it uses as much as digits as its factorization.
10565054131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 10565054131 in words is "ten billion, five hundred sixty-five million, fifty-four thousand, one hundred thirty-one".
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