Search a number
-
+
1058577347141 is a prime number
BaseRepresentation
bin11110110011110000010…
…00000111001001000101
310202012101002000222101122
433121320020013021011
5114320431300102031
62130145334203325
7136323350662526
oct17317010071105
93665332028348
101058577347141
11378a38351896
121511ab4b3545
1378a920754b2
1439341dac84d
151c80914c47b
hexf678207245

1058577347141 has 2 divisors, whose sum is σ = 1058577347142. Its totient is φ = 1058577347140.

The previous prime is 1058577347131. The next prime is 1058577347203. The reversal of 1058577347141 is 1417437758501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 989278890625 + 69298456516 = 994625^2 + 263246^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1058577347141 is a prime.

It is a super-2 number, since 2×10585773471412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1058577347131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 529288673570 + 529288673571.

It is an arithmetic number, because the mean of its divisors is an integer number (529288673571).

Almost surely, 21058577347141 is an apocalyptic number.

It is an amenable number.

1058577347141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1058577347141 is an equidigital number, since it uses as much as digits as its factorization.

1058577347141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3292800, while the sum is 53.

The spelling of 1058577347141 in words is "one trillion, fifty-eight billion, five hundred seventy-seven million, three hundred forty-seven thousand, one hundred forty-one".