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1061051000533 is a prime number
BaseRepresentation
bin11110111000010111001…
…00010110011011010101
310202102202110122120220221
433130023210112123111
5114341013024004113
62131235021154341
7136441555460146
oct17341344263325
93672673576827
101061051000533
11379a976a0237
1215177b9bb9b1
13790976ab824
14394d8721acd
151c9013c198d
hexf70b9166d5

1061051000533 has 2 divisors, whose sum is σ = 1061051000534. Its totient is φ = 1061051000532.

The previous prime is 1061051000497. The next prime is 1061051000567. The reversal of 1061051000533 is 3350001501601.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 951157424529 + 109893576004 = 975273^2 + 331502^2 .

It is a cyclic number.

It is not a de Polignac number, because 1061051000533 - 29 = 1061051000021 is a prime.

It is a super-2 number, since 2×10610510005332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1061051000498 and 1061051000507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1061051000593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 530525500266 + 530525500267.

It is an arithmetic number, because the mean of its divisors is an integer number (530525500267).

Almost surely, 21061051000533 is an apocalyptic number.

It is an amenable number.

1061051000533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1061051000533 is an equidigital number, since it uses as much as digits as its factorization.

1061051000533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 25.

The spelling of 1061051000533 in words is "one trillion, sixty-one billion, fifty-one million, five hundred thirty-three", and thus it is an aban number.